Question

x log y +y log x=1 .find y^xand x^y

Answer 1

Step-by-step explanation:

xlogy + ylogx = 1

=> log(y^x) + log(x^y) = 1

=> log (y^x * x^y) = log 10 base 10

=> y^x * x^y = 10

Answer 2

HOPE IT HELPS :

x JOKER ALWAYS x

ANSWER :

$xlogy + ylogx = 1\\log y^{x} + log x^{y} = 1\\log ( y^{x} . x^{y} ) = 1\\y^{x} . x^{y} = 10$