Question

X=LogBC base A, Y=LogCA base B , Z=LogAB base C then find the value of X+Y+Z is:​

Answer 1

Answer:

$\longrightarrow$

Step-by-step explanation:

$x + y + z = log_{a}(bc) + log_{b}(ca) + log_{c}(ab)$

$= \frac{ log(bc) }{loga} \times \frac{logca}{logc} \times \frac{logab}{c} = 1$