Question

X ^ (m+n) × x ^ (n+1) × x ^(l+m) / (x ^ m × x ^ n × x ^1)^2

Answer 1

Answer:

here is your answeer

Step-by-step explanation:

( x^{l} / x^{m})  ^{1/lm}.  ( x^{m} / x^{n})  ^{1/mn}. ( x^{n} / x^{l})  ^{1/nl}

= ( x^{l-m} )  ^{1/lm}. ( x^{m-n} )  ^{1/mn}. ( x^{n-l}) ^{1/nl}

= x^{(l-m)/lm}. x^{(m-n)/mn}. x^{(n-l)/nl}

= x^{(l-m)/lm+(m-n)/mn+(n-l)/nl}  

= x^{(ln-mn+lm-ln+mn-lm)/lmn}

= x^{0}  

=1 (Proved)