Question

x^m y^n = a^m+n then dy/dx is

Answer 1

x^m.y^n = a^m+n

Differentiating with respect to x =>

d/dx (x^m.y^n) = d/dx (a^m+n)

x^m.d/dx(y)^n + y^n.d/dx(x)^m = 0

x^m.ny^(n-1).dy/dx + y^n.mx^(m-1) = 0

dy/dx = - {mx^(m-1).y^n}/ny^(n-1).x^m

dy/dx = - { m.x^(m-1-m).y^(n-n+1) }/n

dy/dx = - m.y/n.x

dy/dx = -my/nx........●



Hope it was helpful.