x minus 1 is a factor of the polynomial p x is equal to x cube minus 2 x square - x + 2 is it true or false
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Step-by-step explanation:
1. Find zero of the factor (x - 1)
x - 1 = 0
x = 1
Put x = 1 in the given equation ,
x^3 - 2x^2 - x + 2
(1)^3 - 2(1)^2 - (1) + 2
= 1 - 2 - 1 + 2
= 0
Therefore, (x-1) is the factor of p(x).
Hope it helps.
Please nark it as brilliant.
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