Question

x minus 2 is factor of polynomial x cube minus 2 aX square + a x minus 8 then find value of a​

Answer 1

Solution :

Let p(x)=x³-2ax²+ax-8

It is given that (x-2) is a

factor of p(x).

Therefore ,

p(2) = 0

=> 2³-2a×2² + a×2 - 8 = 0

=> 8 - 8a + 2a - 8 = 0

=> -6a = 0

=> a = 0

Therefore ,

a = 0

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