Question

x minus one upon x minus 2 plus x minus 3 upon x minus 4 equal to 10.3

Answer 1

the answer is x minus one upon x minus to plus plus x minus 3 upon x x minus 4 equals to 10. 3 therefore therefore x is equal to 4 x is equal to the sum of minus of address of 1

Answer 2

Answer:

The value of x = 2.1 and x=4.1

Step-by-step explanation:

Given: $\dfrac{x-1}{x-2}+\dfrac{x-3}{x-4}=10.3$

T solve: x

Here we have complex rational equation and to solve for x

First we make common denominator and then make quadratic equation.

$\dfrac{(x-1)(x-4)}{(x-2)(x-4)}+\dfrac{(x-3)(x-2)}{(x-4)(x-2)}=10.3$

$\dfrac{x^2-5x+4+x^2-5x+6)}{x^2-6x+8}=10.3$

$\dfrac{2x^2-10x+10)}{x^2-6x+8}=10.3$

$2x^2-10x+10=10.3(x^2-6x+8)$

$2x^2-10x+10=10.3x^2-61.8x+82.4$

$8.3x^2-51.8x+72.4=0$

Using quadratic formula, $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

a=8.3 , b=-51.8 , c=72.4

$x=\dfrac{51.8\pm\sqrt{51.8^2-4(8.3)(72.4}}{2(8.3)}$

$x\approx 2.1$

$x\approx 4.1$

Hence, The value of x = 2.1 and x=4.1