x mL of 0.5 M HCl aq. solution is mixed with y mL of 0.25 M HCl aq. solution. If 1 L of resultant solution is formed having 0.4 M w.r.t. HCl, then x and y are respectively
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The value of x and y is 600 and 400 ml respectively.
Given:
M1 = 0.5 M
V1 = x ml
M2 = 0.25 M
V2 = y ml
M = 0.4 M
V = 1 L or 1000 ml
To Find:
The value of x and y.
Solution:
We know the formula,
M1V1 + M2V2 = MV
0.5*x + 0.25*y = 0.4*1000
On solving we get,
2x + y = 1600 ------------- (1)
we know, x+y = 1000 ml -----------(2)
y = 1000 - x substitute in (1)
We get, 2x + 1000 - x = 1600
x = 600 ml substitute in (2)
We get, y = 1000 - 600
= 400 ml
Hence, The value of x and y is 600 and 400 ml respectively.
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