X moles of lead acetate and 0.1mole of acetic acid, were taken in one litre solution to make a sol of ph 5.04,the value x will be....The ph of acetic acid is 4.7
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Explanation:
pH = pKa +ln(Salt/acid)
5.04=4.74+ ln(x/.1)
.3= ln (x/.1)
10^.3 = x/.1
2=x/.1
.2=x
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