X’moles of N2, gas at S.T.P. conditions occupy a volume of 10 litres, then the volume of “2x’ moles of CH4, at 273°C and 1.5 atm is?
1) 20 lit 2) 26.6 lit 3) 5 lit 4) 16.6 lit
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Explanation:
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'x' moles of N
2
gas at S.T.P conditions occupy a volume of 10 lit then the volume of '2x' moles of CH
4
at 273
∘
C and 1.5 atm is?
Medium
Solution
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Correct option is B)
Consider the given value,
n=x
P=1.5 atm
V=10 lit
T=273
∘
C
R=?
S.T.P=1atmat0
∘
C
PV=nRT
1×10=x×R×273
10=x×R×273
R=
(x×273)
10
If you meant 273K
Therefore,
(
2
3
)×V=2x×(273+273)×
(273x)
10
(
2
3
)×V=20×2
V=40×(
3
2
)
V=
3
80
V=26.6Liters
Answered by
1
Answer:
26.68litres
Explanation:
x=10/22.4
X=25/56
2x=25/28
PV=nrt
1.5*V=25/28*0.0821*546
V=0.821*5*91/14
V=373.555/14
V=26.68
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