Question

x moles of N2 gas at s.t.p. conditions occupy a volume of 10litres, then the volume of 2x moles of CH4 at 273°C and 1.5 atm is​

Answer 1

Answer:

(n)N2/(n)CH4=. (PV/RT)N2. × (RT/PV)CH4

x/2x. = 1×10/R273. ×R 546/V1.5

1/2. =. 10×546/273 ×1.5 V

V. =22.2 L

Answer 2

Answer:

22.4

Explanation:

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