Question

X moles of potasium chromate oxidises 2 molws of ferrous oxalate in acidic medium ,then x is

Answer 1

The following equations are essential in the answering of the question.

Perhaps, you need for the global writing  

In Acidic medium.  

K₂Cr₂O₇(aq) + 2 FeC₂O4(aq) + 14 H+(aq) -----> 2 K+(aq) + 2 Cr³⁺(aq) + 2 Fe³+(aq) + 4 CO₂(g) + 7 H2O(l)  

In basic medium  

K₂Cr₂O₇(aq) + 2 FeC₂O₄(aq) + 8 OH-(aq) + 3 H2O(l) ---> 2 K+(aq) + 2 Cr(OH)⁻⁴(aq) + 2 Fe(OH)3(s)  

+ 4 CO₃(aq)

Since the oxidation is in acidic medium, the mole ratio is :

1 : 2

We therefore need 0.5moles to oxidize one mole of ferrous oxalate.