X moles of potassium dichromate oxidises 1 mole of ferrous oxalate in acidic medium. Here X is
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Answered by
52
The following equations are essential in the answering of the question.
Perhaps, you need for the global writing
In Acidic medium.
K₂Cr₂O₇(aq) + 2 FeC₂O4(aq) + 14 H+(aq) -----> 2 K+(aq) + 2 Cr³⁺(aq) + 2 Fe³+(aq) + 4 CO₂(g) + 7 H2O(l)
In basic medium
K₂Cr₂O₇(aq) + 2 FeC₂O₄(aq) + 8 OH-(aq) + 3 H2O(l) ---> 2 K+(aq) + 2 Cr(OH)⁻⁴(aq) + 2 Fe(OH)3(s)
+ 4 CO₃(aq)
Since the oxidation is in acidic medium, the mole ratio is :
1 : 2
We therefore need 0.5moles to oxidize one mole of ferrous oxalate.
Perhaps, you need for the global writing
In Acidic medium.
K₂Cr₂O₇(aq) + 2 FeC₂O4(aq) + 14 H+(aq) -----> 2 K+(aq) + 2 Cr³⁺(aq) + 2 Fe³+(aq) + 4 CO₂(g) + 7 H2O(l)
In basic medium
K₂Cr₂O₇(aq) + 2 FeC₂O₄(aq) + 8 OH-(aq) + 3 H2O(l) ---> 2 K+(aq) + 2 Cr(OH)⁻⁴(aq) + 2 Fe(OH)3(s)
+ 4 CO₃(aq)
Since the oxidation is in acidic medium, the mole ratio is :
1 : 2
We therefore need 0.5moles to oxidize one mole of ferrous oxalate.
Answered by
6
Answer:
Explanation:
The following equations are essential in the answering of the question.
Perhaps, you need for the global writing
In Acidic medium.
K₂Cr₂O₇(aq) + 2 FeC₂O4(aq) + 14 H+(aq) -----> 2 K+(aq) + 2 Cr³⁺(aq) + 2 Fe³+(aq) + 4 CO₂(g) + 7 H2O(l)
In basic medium
K₂Cr₂O₇(aq) + 2 FeC₂O₄(aq) + 8 OH-(aq) + 3 H2O(l) ---> 2 K+(aq) + 2 Cr(OH)⁻⁴(aq) + 2 Fe(OH)3(s)
+ 4 CO₃(aq)
Since the oxidation is in acidic medium, the mole ratio is :
1 : 2
We therefore need 0.5moles to oxidize one mole of ferrous oxalate.
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