Math, asked by tjjaichandar0007, 10 months ago

x^(n+1) < x^n
Which 'n' value in put... ​

Answers

Answered by sujathajakku
0

Answer:

x^(n+1)<x^n

x^(n+1)/x^n<1

x^n+1-n< 1

x^1 < 1

Possible for all values of n if x is less than 1

no value of n will satisfy if x is a positive integer

hope it helps!!

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