x^(n+1) < x^n
Which 'n' value in put...
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Answer:
x^(n+1)<x^n
x^(n+1)/x^n<1
x^n+1-n< 1
x^1 < 1
Possible for all values of n if x is less than 1
no value of n will satisfy if x is a positive integer
hope it helps!!
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