(x^n y^-m)^5×(x^3y^-5)^-5
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Answer:
m=17/4,n=-1/5
Step-by-step explanation:
If the condition is infinitely many solutions it is a1/a2=b1/b2=c1/c2
2m-1/3=3/n-1=-5/-2
taking a1/a2=c1/c2
2m-1/3=-5/-2
-2[2m-1]=-5[3]
=-4m+2=-15
-4m=-15-2
=-17
m=-17/-4=17/4
m=17/4
taking b1/b2=c1/c2
=3/n-1=-5/-2
5[n-1]=-2[3]
=5n-5=-6
5n=-6+5
=-1
n=-1/5
the value of m=17/4 and n=-1/5
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