Math, asked by saviteshparauha00, 4 months ago

x और y ऐसी दो संख्याएँ हैं जिनका माध्य
अनुपात 16 है और तृतीय अनुपात 128 है।।
xऔर y का मान क्या है?

Answers

Answered by pulakmath007
0

SOLUTION

GIVEN

x and y are two numbers such that mean proportion is 16 and third proportion is 128

TO DETERMINE

The value of x and y

EVALUATION

Here the given numbers are x and y

Now third proportion is 128

So we have

x : y = y : 128

 \displaystyle \sf \implies \:  \frac{x}{y}  =  \frac{y}{128}

 \displaystyle \sf \implies \:   {y}^{2}  = 128x \:  \:  \:  \:  \:  -  -  -  - (1)

Again mean proportion is 16

So we have

 \sf \:  \sqrt{xy}  = 16

 \displaystyle \sf \implies \:  xy =  {16}^{2}

 \displaystyle \sf \implies \:  \frac{ {y}^{2} }{128}  . y =  {16}^{2}

 \displaystyle \sf \implies \:  \frac{ {y}^{3} }{128}   =  {16}^{2}

 \displaystyle \sf \implies \:   {y}^{3}  =  {16}^{2}  \times 128

 \displaystyle \sf \implies \:   {y}^{3}  =  16 \times 16  \times 128

 \displaystyle \sf \implies \:   {y}^{3}  =  16 \times 16  \times 16 \times 8

 \displaystyle \sf \implies \:   {y}^{}  =   \sqrt[3]{ 16 \times 16  \times 16 \times 8}

 \displaystyle \sf \implies \:  y = 16 \times 2

 \displaystyle \sf \implies \:  y = 32

From Equation 1 we get

 \displaystyle \sf {y}^{2}  = 128x

 \displaystyle \sf \implies \:   {32}^{2}  = 128x

 \displaystyle \sf \implies \:   128x = 32 \times 32

 \displaystyle \sf \implies \:   x = 8

FINAL ANSWER

x = 8 , y = 32

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Answered by RvChaudharY50
1

Answer :-

→ माध्य अनुपात = √(xy)

→ 16 = √(xy)

→ 256 = xy

→ x = (256/y) -------- (1)

अब,

→ तृतीय अनुपात = 128

→ y² = x * 128

→ y² = 128x --------- (2)

अत, (1) का मान (2) में रखने पर,

→ y² = 128 * (256/y)

→ y³ = 128 * 256

→ y = 32

इसलिए,

→ x = 256/32 = 8

x का मान 8 और y का मान 32 होगा ll

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