x और y ऐसी दो संख्याएँ हैं जिनका माध्य
अनुपात 16 है और तृतीय अनुपात 128 है।।
xऔर y का मान क्या है?
Answers
SOLUTION
GIVEN
x and y are two numbers such that mean proportion is 16 and third proportion is 128
TO DETERMINE
The value of x and y
EVALUATION
Here the given numbers are x and y
Now third proportion is 128
So we have
x : y = y : 128
Again mean proportion is 16
So we have
From Equation 1 we get
FINAL ANSWER
x = 8 , y = 32
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Answer :-
→ माध्य अनुपात = √(xy)
→ 16 = √(xy)
→ 256 = xy
→ x = (256/y) -------- (1)
अब,
→ तृतीय अनुपात = 128
→ y² = x * 128
→ y² = 128x --------- (2)
अत, (1) का मान (2) में रखने पर,
→ y² = 128 * (256/y)
→ y³ = 128 * 256
→ y = 32
इसलिए,
→ x = 256/32 = 8
x का मान 8 और y का मान 32 होगा ll
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