Question

x- ಅಕ್ಷದಿಂದ p (3,5) ಬಿಂದುವಿಗೆ ಇರುವ ಸಮಾಂತರ ದೂರ​

Answer 1

SOLUTION

TO DETERMINE

The distance of P(3,5) from x axis

EVALUATION

Here the given point P(3,5)

Thus

Abscissa = 3 unit

Ordinate = 5 unit

Thus distance of P(3,5) from x axis

= Ordinate of P

= 5 unit

FINAL ANSWER

Hence the distance of P(3,5) from x axis

= 5 unit

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