Question

(x+p) is the common factor of x2+ax+b and x2+cx+d then value of p​

Answer 1

as (x+p) is a common factor of

${x}^{2} + ax + b \: and \\ {x}^{2} + cx + + d$

therefore, x=-p must satisfy the above equations

so,

${ (- p)}^{2} + a( - p) + b = 0 \\ {p}^{2} - ap + b = 0 \: \: \: \: \: \: \: ...(1) \\ and \\ {( - p)}^{2} + c( - p) + d = 0 \\ {p}^{2} - cp + d = 0 \: \: \: \: \: \: \: ...(2) \\ \: \: \: \: \: applying \: (1) - (2) \: we \: get \\ ( {p}^{2} - ap + b) - ( {p}^{2} - cp + d) = 0 \\ (c - a)p - (d - b) = 0 \\ p = \frac{d - b}{c - a}$

Answer 2

Answer:

This is your ANSWER!

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