(x+p)squared +q find value of p and q
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Answer:
x^2+6x-2 = (x+p)^2+q
=> x^2+6x-2= x^2 +p^2 + 2px + q
now, compare co-efficient of both sides....
co-efficient of x on LHS = 6, on RHS = 2p
so, 6 = 2p
=> p = 3
Step-by-step explanation:
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