X^p upon x^p + x^q + 1 upon x^p-q +1
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Answer:
Step-by-step explanation:
p+q = 2r ——-proved
(p+q)/2 = r
Substituting the value of r in pq-r(p+q)
pq-(p+q)/2 *(p+q)
Pq - [(p+q)^2 ] /2
[2pq-(p+q)^2)]/2
[2pq-(p^2+2pq+q^2) ]/ 2
[2pq - p^2–2pq- q^2 ]/ 2
(-p^2- q^2)/ 2
-1(p^2+q^2)/2
-1(p^2+q^2)/ 2 ———proved.
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