Math, asked by farzeenali6154, 9 months ago

X^p upon x^p + x^q + 1 upon x^p-q +1

Answers

Answered by abhinavpratatpsingh4
0

Answer:

Step-by-step explanation:

p+q = 2r ——-proved

(p+q)/2 = r

Substituting the value of r in pq-r(p+q)

pq-(p+q)/2 *(p+q)

Pq - [(p+q)^2 ] /2

[2pq-(p+q)^2)]/2

[2pq-(p^2+2pq+q^2) ]/ 2

[2pq - p^2–2pq- q^2 ]/ 2

(-p^2- q^2)/ 2

-1(p^2+q^2)/2

-1(p^2+q^2)/ 2 ———proved.

Similar questions