x/p+y/q=2, x+y=p+q are satisfied by the values given by the pair.
Answers
Answered by
147
Hi ,
According to the given question,
i ) x + y = p + q
x = p + q - y ---------( 1 )
ii ) x / p + y / q = 2
Multiply each term with pq we get
qx + py = 2pq ---------( 2 )
Put x value , from ( 1 ) in equation ( 2)
q( p + q - y) + py = 2pq
pq + q^2 - qy + py = 2pq
- qy + py = 2pq - pq - q^2
y ( - q + p) = pq - q^2
y ( p - q ) = q ( p - q )
y = q ( p - q )/ ( p - q )
y = q -----( 3 )
Put y = q in ( 1 )
x = p + q - q
x = p
Therefore ,
x = p and y = q
I hope this helps you.
****
According to the given question,
i ) x + y = p + q
x = p + q - y ---------( 1 )
ii ) x / p + y / q = 2
Multiply each term with pq we get
qx + py = 2pq ---------( 2 )
Put x value , from ( 1 ) in equation ( 2)
q( p + q - y) + py = 2pq
pq + q^2 - qy + py = 2pq
- qy + py = 2pq - pq - q^2
y ( - q + p) = pq - q^2
y ( p - q ) = q ( p - q )
y = q ( p - q )/ ( p - q )
y = q -----( 3 )
Put y = q in ( 1 )
x = p + q - q
x = p
Therefore ,
x = p and y = q
I hope this helps you.
****
Answered by
16
A.T.Q.
i ) x + y = p + q
x = p + q - y ---------( 1 )
ii ) x / p + y / q = 2
Multiply each term with pq we get
qx + py = 2pq ---------( 2 )
Put x value , from ( 1 ) in equation ( 2)
q( p + q - y) + py = 2pq
pq + q^2 - qy + py = 2pq
- qy + py = 2pq - pq - q^2
y ( - q + p) = pq - q^2
y ( p - q ) = q ( p - q )
y = q ( p - q )/ ( p - q )
y = q -----( 3 )
Put y = q in ( 1 )
x = p + q - q
x = p and y = q
Hope it helps you please follow me
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