Question

x = p, y = q is a solution of the equations x + 2 y+ 1 = 0 and 2 x– 3 y – 12= 0,

then the values of p and q are respectively:​

Answer 1

Answer:

p=-2 & q=4

Step-by-step explanation:

$x + 2y = - 1$

and,

$2x - 3y = 12$

multiply equation first by 2,

$2x + 4y = - 2$

subtract equation second from first,

$\: \: 2x + 4y = - 2 \\ - 2x \frac{ - }{ + } 3y = \frac{+}{-}12$

ans,

$0 + 7y = - 14$

$y = \frac{ - 14}{7}$

$y = - 2$

put y = -2 in equation first

$x + ( - 2)2 = - 1$

$x - 4 = - 1$

$x = - 1 + 5$

$x =4$

$x = p \: and \: y = q$

therefore, p = -2

q = 4