Question

x plus one upon x minus 1 plus x minus 2 upon X + 2 is equal to 3​

Answer 1

$\huge{\bold{\underline{Solution}}}$

$x + \frac{1}{x - 1} + x - \frac{2}{x + 2} = 3 \\ \\ 2x + \frac{1}{x - 1} - \frac{2}{x + 2} = 3 \\ \\ 2x + \frac{1 - 2}{(x - 1)(x + 2)} = 3 \\ \\ 2x + \frac{ - 1}{ ({x}^{2} + 2x - x - 2 )} = 3 \\ \\ 2x - 1 = 3( {x}^{2} + 2x - x - 2) \\ \\ 2x - 1 = 3 {x}^{2} + 3x - 6 \\ \\ 3 {x}^{2} + 2x - 3x = - 6 + 1 \\ \\ 3 {x}^{2} - x = - 5 \\ \\ 3 {x}^{2} - x + 5 = 0$

If u want the value of x then u can split the middle term to know the value of x