Question

X plus one upon x x x minus one upon x x x square + 1 upon x square x x raise to the power 4 + 1 upon X raise to the power 4

Answer 1

Given :  (x + 1/x) (x - 1/x) (x 2 + 1/x 2 ) (x 4 + 1/x 4 )

To find : Simplify

Solution:

 (x + 1/x) (x - 1/x) (x² + 1/x² ) (x⁴ + 1/x⁴)

Using identity (a + b)(a - b) = a² - b²

a = x ,  b = 1/x

=(x² - 1/x² ) (x² + 1/x² ) (x⁴ + 1/x⁴)

now a = x²  & b = 1/x²

= ( (x²)² -(1/x²)²)(x⁴ + 1/x⁴)

= (x⁴ - 1/x⁴)(x⁴ + 1/x⁴)

now a = x⁴  & b = 1/x⁴

= ((x⁴)² - (1/x⁴)²)

= x⁸ - 1/x⁸

 (x + 1/x) (x - 1/x) (x² + 1/x² ) (x⁴ + 1/x⁴) = x⁸ - 1/x⁸

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Answer 2

Answer:

I hope it's helpful for u...