x plus y whole to the power of 12
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(x+y)¹²=x¹²+12x¹¹y+66x¹⁰y²+220x⁹y³+495x⁸y⁴+792x⁷y⁵+924x⁶y⁶+792x⁵y⁷
+495x⁴y⁸+220x³y⁹+66x²y¹⁰+12xy¹¹+y¹².
+495x⁴y⁸+220x³y⁹+66x²y¹⁰+12xy¹¹+y¹².
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so , your question is that (x+y)^12 .
So, the answer is that
we written this
(x+y)^12={(x+y)^6}^2
by using identity (a+b)^2=a^2+2 ab+b^2
we use this identity in this question
So , after solving that the answer is
x^12+2x^6y^6+y^12
So, the answer is that
we written this
(x+y)^12={(x+y)^6}^2
by using identity (a+b)^2=a^2+2 ab+b^2
we use this identity in this question
So , after solving that the answer is
x^12+2x^6y^6+y^12
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