Question

x power 6 -8 by x power 2 -2

Answer 1

$\frac{ {x}^{6} - 8 }{ {x}^{2} - 2} \\ = \frac{ { {x}^{2} }^{3} - {2}^{3} }{ {x}^{2} - 2} = \frac{( {x}^{2} - 2)( { {x}^{2} }^{2} + 2 {x}^{2} + {2}^{2} ) }{( {x}^{2} - 2) } \\ since \: {x}^{3} - {y}^{3} = (x - y)( {x}^{2} - xy + {y}^{2} ) \\ = {x}^{4} + 2 {x}^{2} + 4$
Hope this is ur required simplified form.

Proud to help you

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ Equation:\\\\\rightarrow \frac{x^6-8}{x^2-2}$

$\therefore a^6 = (a^2)^3 \ and \ 8 = (2)^3\\\\\ formula: \\\\ \ (a^3 -b^3) = (a-b) (a^2+b^2+ab) \\\\\ Solve: \\\\\rightarrow \frac{x^6-8}{x^2-2} \\\\\rightarrow \frac{(a^2)^3-(2)^3}{(x^2-2)}\\\\\rightarrow \frac{(a^2-2)((a^2)^2+(2^2)+a^2.2)}{(x^2-2)}\\\\\rightarrow \frac{(a^2-2)(a^4+4+2a^2)}{(x^2-2)}\\\\\rightarrow (a^4+2a^2+4)$

Learn more:

• Simplify: https://brainly.in/question/12722253