Question

X power n - 27 divisible by x-3 when n is equal to

Answer 1

Heyy mate ❤✌✌❤

Here's your Answer...

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n = 3.

By using identity formula of cubes i.e. a^3-b^3=(a-b)*(a^2+a*b+b^2)


therefore, (x^3-27)/(x-3) can be expanded as
=(x^3-3^3)/(x-3)

=[(x-3)*(x^2+3*x+3^2)]/(x-3)
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