Question

-x+py=1
px-y=1
find p
by elimination method
please answer in detail and please don't give silly answer

Answer 1

py-x=1 *y

px-y=1 *x

py²-xy=y......(1)

px²-xy=x......(2)

Subtracting eq 1 and 2

p(y²-x²)=(y-x)

p[(y+x)(y-x)]=(y-x)

p(y+x)=(y-x)/(y-x)

py+px=1

p(y+x)=1

p= 1/(y+x)