(x-q) (p-q) =(x+q) (p+q)
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nikki1231
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given,
=> p+q/x-q = p-q/x+q
=> p+q(x+q) = p-q(x-q)
=> px+pq+xq+q² = px-pq-xq+q²
=> px+pq+xq+q²-px+pq+xq-q² = 0
=> 2pq+2xq = 0
=> 2(pq+xq) = 0
=> pq+xq = 0
=> xq = -pq
=> x = -pq/q
=> x = -p
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x-q-x+q=p+a+-p+q
x-x-q+q=p-p+q-q
0=0
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