x= r.cosAcosB,y=rcosA.sinB and Z=r.sinA then prove that x²+y²+z²=r²
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Answer:
cos²A + sin²A = 1
cos²B + sin²B = 1
Step-by-step explanation:
x = rcosAcosB
y = rcosAsinB
z = rsinA
x² + y² + z²
r²cos²Acos²B + r²cos²Asin²B + r²sin²A
r²cos²A(cos²B+sin²B) + r²sin²A
r²cos²A + r²sin²A
r²(cos²A + sin²A)
r²
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