X raise to power 4 + 1 upon x raise to power 4 equals to 322 find the value of x minus one upon x
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Answered by
7
Answer :
Given,
x⁴ + 1/x⁴ = 322
⇒ (x² + 1/x²)² - (2 × x² × 1/x²) = 322
⇒ (x² + 1/x²)² - 2 = 322
⇒ (x² + 1/x²)² = 324
⇒ x² + 1/x² = √324, taking the positive value
⇒ x² + 1/x² = 18
⇒ (x - 1/x)² + (2 × x × 1/x) = 18
⇒ (x - 1/x)² = 18 - 2
⇒ (x - 1/x)² = 16
⇒ x - 1/x = ± 4
Thus, x - 1/x = ± 4
#MarkAsBrainliest
Given,
x⁴ + 1/x⁴ = 322
⇒ (x² + 1/x²)² - (2 × x² × 1/x²) = 322
⇒ (x² + 1/x²)² - 2 = 322
⇒ (x² + 1/x²)² = 324
⇒ x² + 1/x² = √324, taking the positive value
⇒ x² + 1/x² = 18
⇒ (x - 1/x)² + (2 × x × 1/x) = 18
⇒ (x - 1/x)² = 18 - 2
⇒ (x - 1/x)² = 16
⇒ x - 1/x = ± 4
Thus, x - 1/x = ± 4
#MarkAsBrainliest
Answered by
3
x⁴ + 1/x⁴ = 322
Adding 2 [ x² × 1/x²] on both sides,
x⁴ + 1/x⁴ + 2 [x² × 1/x⁴] = 322 + 2 [x² × 1/x²]
=> (x² + 1/x²)² = 324
=> x² + 1/x² = √324
=> x² + 1/x² = 18
Adding -2 [x × 1/x] on both sides,
=> x² + 1/x² - 2 [x × 1/x] = 18 - 2 [x × 1/x]
=> (x - 1/x)² = 18 - 2
=> (x - 1/x)² = 16
=> x - 1/x = 4 [your answer]
I hope this will help you
(-:
Adding 2 [ x² × 1/x²] on both sides,
x⁴ + 1/x⁴ + 2 [x² × 1/x⁴] = 322 + 2 [x² × 1/x²]
=> (x² + 1/x²)² = 324
=> x² + 1/x² = √324
=> x² + 1/x² = 18
Adding -2 [x × 1/x] on both sides,
=> x² + 1/x² - 2 [x × 1/x] = 18 - 2 [x × 1/x]
=> (x - 1/x)² = 18 - 2
=> (x - 1/x)² = 16
=> x - 1/x = 4 [your answer]
I hope this will help you
(-:
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