X-ray beam of wavelength 2.9 AU is diffracted from the plane of cubic crystal. The first order diffraction is obtained at the angle of 35°. Calculate the spacing between the planes.
Answers
Answered by
0
Answer:
ANSWER
The Bragg’s Law of diffraction is given as
2dsinθ=nλ
By substituting the values given in the above equation we get
2×2.8×10
10
sinθ=1×10
10
m
The value of the angle is
θ=sin
−1
(
5.6
1
)
Hence the angle is17.8
∘
Answered by
2
Answer:
253×10^-10 m
Explanation:
X-ray beam of wavelength 2.9 AU is diffracted from the plane of cubic crystal. The first order diffraction is obtained at the angle of 35°. Calculate the spacing between the planes.
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