Physics, asked by amritpaudel516, 8 months ago

X-ray beam of wavelength 2.9 AU is diffracted from the plane of cubic crystal. The first order diffraction is obtained at the angle of 35°. Calculate the spacing between the planes.​

Answers

Answered by krishivgoyal2
0

Answer:

ANSWER

The Bragg’s Law of diffraction is given as

2dsinθ=nλ

By substituting the values given in the above equation we get

2×2.8×10

10

sinθ=1×10

10

m

The value of the angle is

θ=sin

−1

(

5.6

1

)

Hence the angle is17.8

Answered by khansarif62733
2

Answer:

253×10^-10 m

Explanation:

X-ray beam of wavelength 2.9 AU is diffracted from the plane of cubic crystal. The first order diffraction is obtained at the angle of 35°. Calculate the spacing between the planes.

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