x-ray of wavelength 1Ao are incident on a material. (a) The ejected electrons at a certain angle have kinetic energy 200 ev.
Answers
Answered by
0
Answer:
The de Broglie wavelength for electron = λ=h/p=c/ν
Given λ
e
=λ
p
KE of electron = 1/2×m×v
2
=1/2×p×v
e
Substituting for p in the above equation, we get
K.E of electron :
2λ
e
hv
e
∴λ
e
=
2×KE
e
h×v
e
The K.E of photon is given by :
λ
p
hc
∴λ
p
=
KE
p
h×c
Given that the wavelengths are equal .
Taking ratio we get :
2×KE
e
v
e
=
KE
p
c
Then,
KE
e
KE
p
=
v
e
2×c
=
1.5×10
8
2×3×10
8
=4
Explanation:
Similar questions