Question

X-ray wavelength of 0.4500 nm scattered from free electrons in a target. What is wavelength of photon scattered at 60 degree

Answer 1

From equation Δλ = h/mc [1-cos?]

= [(6.63×10-34 J.s) (1-cos 60°)]/[(9.11×10-31kg) (3.00×108 m/s)]

= 4.5  × 10-10 m

≈ 450 pm

From the above observation we conclude that, the Compton shift of the scatered rays would be 2.2 pm.  

(b) The fractional energy loss frac is,

frac = [E-E'] / E

= [hf – hf '] / hf

= [c/λ – c/λ'] / [c/λ]

= [λ' - λ] / λ'

= Δλ / [λ+Δλ]

Substitution gives,

frac = [450 pm]/[45 pm+45. pm]

hope its help you

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