Question

X=rcosθ y=rsinθ z= r (sinθ+cosθ) find the value of x²+y²-z²

Answer 1

Answer:

-2sinθcosθ r²

Step-by-step explanation:

x²+y²-z²

or (rcosθ)² + (rsinθ)² - (r (sinθ+cosθ))²

or r²cos²θ + r²sin²θ - r² (sinθ+cosθ)²

or r² - r² (sin²θ + cos²θ + 2 sinθcosθ)

or r² (1- 1 - 2sinθcosθ)

or -2sinθcosθ r²

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