x= root[ 3+2 root2] then find the value of x to the power 4 +1/x to the power4
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HELLO DEAR,


--------------( 1 )
1/x⁴ = 1/(17 + 12√2) * (17 - 12√2)/(17 - 12√2)
1/x⁴ = (17 - 12√2)/(289 - 288)
1/x⁴ = (17 - 12√2)---------------( 2 )
adding-----------( 1 ) & -----------( 2 )
x⁴ + 1/x⁴ = (17 + 12√2) + (17 - 12√2)
x⁴ + 1/x⁴ = (17 + 17 + 12√2 - 12√2)
x⁴ + 1/x⁴ = 34
1/x⁴ = 1/(17 + 12√2) * (17 - 12√2)/(17 - 12√2)
1/x⁴ = (17 - 12√2)/(289 - 288)
1/x⁴ = (17 - 12√2)---------------( 2 )
adding-----------( 1 ) & -----------( 2 )
x⁴ + 1/x⁴ = (17 + 12√2) + (17 - 12√2)
x⁴ + 1/x⁴ = (17 + 17 + 12√2 - 12√2)
x⁴ + 1/x⁴ = 34
ps284147:
thanks ones again
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