Question

x=root over 1-cosx/1+cosx

2x/1-x^2

Answer 1

Step-by-step explanation:

Explanation:

Explanation:

Part 1

√1−cosx1+cosx

XXX=√1−cosx√1+cosx

XXX=√(1−cosx)√1+cosx⋅√1−cosx√1−cosx

XXX=1−cosx√1−cos2x

Part 2

Similarly

√1+cosx1−cosx

XXX=1+cosx√1−cos2x

Part 3: Combining the terms

√1−cosx1+cosx+√1+cosx1−cosx

XXX=1−cosx√1−cos2x+

=2/।sinx।