Question

(x-root2)²-2(x+1)=0 factorise ​

Answer 1

Step-by-step explanation:

( x-root )^2 - 2(x+1 ) = x2 + 2 - 2√2x - 2x - 2

= x2 - 2 √2x - 2x

on taking x as common

x( x - 2√2 - 2 )

(x = 0 )( x = 2√2 +2 )

hence this is your answer

hope you will understand.

if you satisfy this answer so please mark me brainlist.

Answer 2

step by step explanation

(x - √2)² - 2( x + 1 )

Here root and squared are cancelled

( x² - 2 ) (-2x - 2) = 0

• x² - 2 = 0

x² = 2

x = √2

• -2x - 2 = 0

-2x = 2

x = 2 / -2

x = -1

Hope it helped brother, pls mark brainliest...