(x-root3y)^2 solve the equation
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Step-by-step explanation:
y=
3
(x) and x+
3
y=2
Solving the above two equations, we get
P=(
2
1
,
2
3
)
Substituting in the equation of L
2
we get
a+
3
b=2 ...(i)
Now the angle enclosed is 45
0
and tan45
0
is 1.
Hence m
1
=−
3
1
and m
2
=
b
−a
Now
1+m
1
m
2
m
1
−m
2
=1
m
1
−m
2
=1+m
1
m
2
3
1
−
b
a
=1+
3
b
a
Hence b−
3
a=b
3
+a
b(1−
3
)=a(1+
3
)
b=
1−
3
a(1+
3
)
...Substituting in (i) we get
a(1+
1−
3
3
(1+
3
)
)=2
a(
1−
3
1−
3
+
3
+3
)=2
a(
1−
3
4
)=2
a=
2
1−
3
Hence b=
2
1+
3
.
Hence a
2
+b
2
=(
2
1−
3
)
2
+(
2
1+
3
)
2
=2
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