Question

(x-root3y)^2 solve the equation

Answer 1

Step-by-step explanation:

y=

3

(x) and x+

3

y=2

Solving the above two equations, we get

P=(

2

1

,

2

3

)

Substituting in the equation of L

2

we get

a+

3

b=2 ...(i)

Now the angle enclosed is 45

0

and tan45

0

is 1.

Hence m

1

=−

3

1

and m

2

=

b

−a

Now

1+m

1

m

2

m

1

−m

2

=1

m

1

−m

2

=1+m

1

m

2

3

1

−

b

a

=1+

3

b

a

Hence b−

3

a=b

3

+a

b(1−

3

)=a(1+

3

)

b=

1−

3

a(1+

3

)

...Substituting in (i) we get

a(1+

1−

3

3

(1+

3

)

)=2

a(

1−

3

1−

3

+

3

+3

)=2

a(

1−

3

4

)=2

a=

2

1−

3

Hence b=

2

1+

3

.

Hence a

2

+b

2

=(

2

1−

3

)

2

+(

2

1+

3

)

2

=2