Question

x=sec²y ko differentiate ​

Answer 1

Answer:

$x = sec {}^{2} y$

$\frac{d(x)}{dx} = \frac{d(sec {}^{2} y)}{dx}$

$1 = tany. \frac{dy}{dx}$

$tany \frac{dy}{dx} = - 1$

$\frac{dy}{dx} = \frac{ - 1}{tany}$

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