Question

X sells his goods 20% cheaper than Y and 20% dearer than Z. How many % is Z's goods cheaper/dearer

than Y's?​

Answer 1

Answer:

33.33%

Step-by-step explanation:

Assuming Charan sells his good for Rs. 100.

Raju's selling price = 1.2 * 100 = Rs. 120.

Assuming Bharat's selling price is Rs. X.

120 = X * 0.8 (Raju sells 20% cheaper than Bharat)

X = 120 * 10/8

X = 150

Therefore Charan's goods are Rs. 50 cheaper than Bharat's.

Which is, (50/150)*100 = 33.33% cheaper.

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Answer 2

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$\huge\sf\underline{Given:}$

X sells his goods 20%

cheaper than Y and 20%

dearer than Z.

$\huge\sf\underline{Explanation:}$

${20% cheaper ⇒ X ∶ Y → (4 ∶ 5)× 3$

${20% dearer ⇒ X ∶ Z → 6 ∶ 5)× 2$

$X ∶ Y ∶ Z → 12 ∶ 15 ∶ 10$

$\huge\sf\underline{Required \: percentage =}$

${(15 - 10)/15} × 100$

$⇒ 33.33%$

∴ Z is 33.33% cheaper than Y.