Question

x sq + 10x + 15 (second degree equation )
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Answer 1

Step-by-step explanation:

$1</p><p></p><p> </p><p></p><p>In general, given a{x}^{2}+bx+cax2+bx+c, the factored form is:</p><p></p><p>a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a})</p><p></p><p>$

$In \ this \ case,a=1, b=10b=10 and c=15c=15.</p><p></p><p>(x-\frac{-10+\sqrt{{10}^{2}-4\times 15}}{2})(x-\frac{-10-\sqrt{{10}^{2}-4\times 15}}{2})</p><p></p><p>$

$3</p><p></p><p> </p><p></p><p>Simplify.</p><p></p><p>(x-\frac{-10+2\sqrt{10}}{2})(x-\frac{-10-2\sqrt{10}}{2})</p><p></p><p></p><p>$

$Factor \ \: out \ the \ \: common \ term 22.</p><p></p><p>(x-\frac{-2(5-\sqrt{10})}{2})(x-\frac{-10-2\sqrt{10}}{2})</p><p></p><p></p><p>$

$Move \ the \ negative \ sign \ to \ the \ left.</p><p></p><p>(x-(-\frac{2(5-\sqrt{10})}{2}))(x-\frac{-10-2\sqrt{10}}{2})</p><p></p><p>$