(x sq-7x+12)÷x-3 plz solve this eg and teach me
Answers
Answered by
1
Hey....✌✌
{x^2 - 7x +12 }÷ x-3
✴ By middle term split ,
{x^2 - 4x - 3x +12 } ÷ x-3
{x (x-4)-3(x-4) } ÷ x-3
{ (x-3) ( x-4)} ÷x-3
x-4
✔ Hope this helps
{x^2 - 7x +12 }÷ x-3
✴ By middle term split ,
{x^2 - 4x - 3x +12 } ÷ x-3
{x (x-4)-3(x-4) } ÷ x-3
{ (x-3) ( x-4)} ÷x-3
x-4
✔ Hope this helps
Answered by
0
Here is your answer dude!
X^2 - 7x + 12 ÷ x-3
==========================
Now factories the equation
=> X^2 -4x - 3x +12 ÷ x-3
=> x ( X -4) -3 (x-4) ÷ x-3
=> (x-3) (x-4) /(x-3)
=> (x-4) ans
X^2 - 7x + 12 ÷ x-3
==========================
Now factories the equation
=> X^2 -4x - 3x +12 ÷ x-3
=> x ( X -4) -3 (x-4) ÷ x-3
=> (x-3) (x-4) /(x-3)
=> (x-4) ans
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