x=(\sqrt(5)+\sqrt(2))/(\sqrt(5)-\sqrt(2)) y=(\sqrt(5)-\sqrt(2))/(\sqrt(5)+\sqrt(2)) find value of 9x^(2)+2xy+y^(2)
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Answer:
9-(x²-2xy+y²)
9-(x²-2xy+y²)9-(x-y)²
9-(x²-2xy+y²)9-(x-y)²3²-(x-y)²
9-(x²-2xy+y²)9-(x-y)²3²-(x-y)²this is in the form a²-b²
9-(x²-2xy+y²)9-(x-y)²3²-(x-y)²this is in the form a²-b²so the factors are (3+x-y) (3-x+y)
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Step-by-step explanation:
11.Solve the following:(Hint: rationalise denominator of x and y seperately) *
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