Math, asked by sharmadivyanand, 7 hours ago

x square - 1 - 6x = 0, find x cube - 1/x cube​

Answers

Answered by sivakamy1315
0

Step-by-step explanation:

x {}^{2}  - 3x  + 2x -6x = 0 \\ x(x - 3) + 2(x - 3) = 0 \\ (x + 2)(x - 3) = 0 \\ x =  - 2 \: or \: 3 \\  \\  \\  \\  \\

x^3= 8 or 27

1/x^3 = 1/8 or 1/27

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