Question

X square + 1/6x-2 please answer this

Answer 1

Answer:

Step-by-step explanation:

Here the given equation is

x²+(1/6x)-2=0

multiplying the above equation by 6 we get

6x²+x-12=0

or,6x²+9x-8x-12=0

or,3x(2x+3)-4(2x+3)=0

or,(3x-4)(2x+3)=0

Hence the zeros of the polynomial are

x=4/3 andx=-3/2

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