Question

X square + 1 by x square is equals to 7 then find the value of 7 x cube + 8 x minus 7 by x cube minus 8 by X

Answer 1

$\frac{ {x}^{2} + 1 }{ {x}^{2} } = 7$
=>
${x}^{2} + 1 = 7 {x}^{2} = > 6 {x}^{2} = 1$
=>
${x}^{2} = \frac{1}{6}$
=> x=1/√6 .
$\frac{7 {x}^{3} + 8x - 7 }{ {x}^{3} - 8}$
find the value of the above quantity
$\frac{ \frac{7}{6 \sqrt{6} } + \frac{8}{ \sqrt{6} } - 7}{ \frac{1}{6 \sqrt{6} } - 8}$
=> 7+8(6)-7(6√6)/1-8(6√6) = 55-42√6/1-48√6 =
-47.8785692/-116.575508 = 0.410 approximately.
Hope it helps you....

Answer 2

Answer:

Step-by-step explanation: