Question

X square + 1 has no real zeros

Answer 1

x²+1=0

x²=-1

x=√-1

x=i ∉R

(or)

x=-b± √b²-4ac/2a

here
a=1
b=0
c=1

x=0 ± √0-4/2(1)

=0±√-4/2

=±2i/2

= +i or -i

i belongs to complex numbers.so x²+1 has no real zeroes

hope helped !

Answer 2

hi friend lets try finding zeroes of given polynomial
x²- (-√1)²
{x+(-√1)}{x-(√1)} Using identity a²-b²=(a+b)(a-b)

{x-1}{x+1}
x= 1 , x=-1
the zeroes of the given polynomial are 1 and -1
hope it will help you