Question

X square + 1 upon x square minus 2 minus 3 X + 3 upon x​

Answer 1

Step-by-step explanation:

So, x² + 1/x² - 2 - 3x + 3/x

= (x - 1/x)² + 2x.1/x - 2 - 3(x - 1/x)

Note :- a² + b² = (a - b)² + 2ab , here in place of a use x and in place of b use 1/x then, x² + 1/x² = (x - 1/x)² + 2x.1/x ]

= (x - 1/x)² + 2 - 2 -3(x - 1/x)

= (x - 1/x)² - 3(x - 1/x)

= (x - 1/x)(x - 1/x - 3)

Hence, factorization of given polynomial is (x - 1/x)(x - 1/x - 3)

Answer 2

Answer:

x²+1/x²-2-3x+3/2

(x-1/x)² +2x1/x-2-3(x-1/x)

-a²+b²=(a-b)²+2ab,

x²+1/x²=(x-1/x²) +2x-1/x

=(x-1/x)²+2-2-3(x-1/x)

=(x-1/x)² -3(x-1/x)

=(x-1/x)(x-1/x-3) answer

Hope it helpful to you.........