Question

X square + 1/x square +x-1/x-4=0

Answer 1

${x}^{2} + \frac{1}{ {x}^{2} } + \frac{x - 1}{x - 4} = 0 \\ \frac{(x - 4) + ( {x}^{3} - {x}^{2}) }{ {x}^{2}(x - 4) } = 0 - {x}^{2}$